Hola a todos :
Alguien tendrá una función que devuelva la diferencia que hay en horas entre 2 fechas ?
Saludos
/* $DOC$
* $FUNCNAME$
* FT_ELAPSED()
* $CATEGORY$
* Date/Time
* $ONELINER$
* Return elapsed time between two days and/or times
* $SYNTAX$
* FT_ELAPSED([ <dStart> ], [ <dEnd> ], ;
* <cTimeStart>, <cTimeEnd>) -> aTimedata
* $ARGUMENTS$
* <dStart> is any valid date in any date format. Defaults to DATE().
*
* <dEnd> is any valid date in any date format. Defaults to DATE().
*
* <cTimeStart> is a valid Time string of the format 'hh:mm:ss' where
* hh is hours in 24-hour format.
*
* <cTimeEnd> is a valid Time string of the format 'hh:mm:ss' where
* hh is hours in 24-hour format.
* $RETURNS$
* A two-dimensional array containing elapsed time data.
* $DESCRIPTION$
* FT_ELAPSED() calculates the elapsed time between two Date/Time events.
*
* It returns an array which contains the following data:
*
* aRetVal[1,1] Integer Days aRetVal[1,2] Total Days (nn.nnnn)
* aRetVal[2,1] Integer Hours aRetVal[2,2] Total Hours (nn.nnnn)
* aRetVal[3,1] Integer Minutes aRetVal[3,2] Total Minutes (nn.nnnn)
* aRetVal[4,1] Integer Seconds aRetVal[4,2] Total Seconds (nn)
* $EXAMPLES$
* FT_ELAPSED(CTOD('11/28/90'), CTOD('11/30/90'), '08:00:00', '12:10:30')
* will return:
*
* aRetVal[1,1] -> 2 (Days) aRetVal[1,2] -> 2.1740 Days
* aRetVal[2,1] -> 4 (Hours) aRetVal[2,2] -> 52.1750 Hours
* aRetVal[3,1] -> 10 (Minutes) aRetVal[3,2] -> 3130.5000 Minutes
* aRetVal[4,1] -> 30 (Seconds) aRetVal[4,2] -> 187830 Seconds
* $END$
*/
FUNCTION FT_ELAPSED(dStart, dEnd, cTimeStart, cTimeEnd)
LOCAL nTotalSec, nCtr, nConstant, nTemp, aRetVal[4,2]
IF ! ( VALTYPE(dStart) $ 'DC' )
dStart := DATE()
ELSEIF VALTYPE(dStart) == 'C'
cTimeStart := dStart
dStart := DATE()
ENDIF
IF ! ( VALTYPE(dEnd) $ 'DC' )
dEnd := DATE()
ELSEIF VALTYPE(dEnd) == 'C'
cTimeEnd := dEnd
dEnd := DATE()
ENDIF
IF( VALTYPE(cTimeStart) != 'C', cTimeStart := '00:00:00', )
IF( VALTYPE(cTimeEnd) != 'C', cTimeEnd := '00:00:00', )
nTotalSec := (dEnd - dStart) * 86400 + ;
VAL(cTimeEnd) * 3600 + ;
VAL(SUBSTR(cTimeEnd,AT(':', cTimeEnd)+1,2)) * 60 + ;
IF(RAT(':', cTimeEnd) == AT(':', cTimeEnd), 0, ;
VAL(SUBSTR(cTimeEnd,RAT(':', cTimeEnd)+1))) - ;
VAL(cTimeStart) * 3600 - ;
VAL(SUBSTR(cTimeStart,AT(':', cTimeStart)+1,2)) * 60 - ;
IF(RAT(':', cTimeStart) == AT(':', cTimeStart), 0, ;
VAL(SUBSTR(cTimeStart,RAT(':', cTimeStart)+1)))
nTemp := nTotalSec
FOR nCtr = 1 to 4
nConstant := IF(nCtr == 1, 86400, IF(nCtr == 2, 3600, IF( nCtr == 3, 60, 1)))
aRetVal[nCtr,1] := INT(nTemp/nConstant)
aRetval[nCtr,2] := nTotalSec / nConstant
nTemp -= aRetVal[nCtr,1] * nConstant
NEXT
RETURN aRetVal
FUNCTION DEMO()
LOCAL dStart, dEnd, cTimeStart, cTimeEnd, n, aDataTest := {}
dStart := CTOD('11/28/90')
dEnd := CTOD('11/30/90')
cTimeStart := "08:00:00"
cTimeEnd := "12:10:30"
aDataTest := FT_ELAPSED(dStart,dEnd,cTimeStart,cTimeEnd)
FOR n = 1 to 4
? aDataTest[n,1], STR(aDataTest[n,2], 12, 4)
?? " "
?? IF(n == 1, 'Days', IF( n== 2, 'Hours', IF( n == 3, 'Mins.', 'Secs.')))
NEXT
RETURN NIL
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