start at the end and go back in an array - RESOLVED --

[Otto]

Silvio, is your program running if you start at the top and with ASCAN?

If yes, you could sort your array for a test only?

Best regards,
Otto

aRData := ASort( aData, nil, nil, { |x,y| x[ 1 ] > y[ 1 ] } )
xbrowse(aRData)

[Silvio.Falconi]

I allready tried last week
ASort( aDataDbf ,,, {|x,y| x[2] > y[2] } ) because you must sort on date field




then using the Aeval but it not run ok , it result 9155 instead of 24

Code: Select all  Expand view  RUN

Function Rit( aData, numero, nWheel,nRecord )
   local nCount   := 0
   local nPos1,nPos2,nPos3,nPos4,nPos5
   local bBlock,cond

      nPos1 := ( nWheel - 1 ) * 5 + 3
      nPos2 := ( nWheel - 1 ) * 5 + 4
      nPos3 := ( nWheel - 1 ) * 5 + 5
      nPos4 := ( nWheel - 1 ) * 5 + 6
      nPos5 := ( nWheel - 1 ) * 5 + 7

     AEval( aData, { |a| If( a[ nPos1 ]   == numero .or. ;
                           a[ nPos2 ] == numero .or. ;
                           a[ nPos3 ] == numero .or. ;
                           a[ nPos4 ] == numero .or. ;
                           a[ nPos5 ] == numero  , , ncount++ ) } )


   return nCount

If you put
AEval( aData, { |a| If( a[ nPos1 ] == numero .or. ;
a[ nPos2 ] == numero .or. ;
a[ nPos3 ] == numero .or. ;
a[ nPos4 ] == numero .or. ;
a[ nPos5 ] == numero , ncount++, ) } )

it result the frequency number not the delay !!!!

[Otto]

Silvio,
What is the "delay"?
You use AEVAL but I think you should use ASCAN?

Best regards,
Otto

[Silvio.Falconi]

We call "delay" of a lottery number the number of draws that have elapsed without that number coming out. A number has a delay of 1 if it just came out, a delay of 30 if it last came out 30 draws ago, and so on.

[Silvio.Falconi]

Found the solution

I Made it with For next cicle