FiveTech Software tech support forums

Posted: **Fri May 27, 2022 8:13 pm**

I have an array created with

AaDd(aFrequeMax[nRuota],{massimo, &num})

then I have a number for a sample 42 and the nWheel 1

I must found the number 42 on aFrequeMax [nWheel] and return me the second element of this array

How I must make it ?

I tried with
AEval( aData, { |a| If( (a[1] = numero ), nFrequenza:=a[2] , nil ) } )

Posted: **Fri May 27, 2022 8:43 pm**

Dear Silvio,

Please provide a drawing or something to better understand you :-)

Posted: **Fri May 27, 2022 9:47 pm**

Antonio Linares wrote:Dear Silvio,

Please provide a drawing or something to better understand you

sample nWheel = 1

I have to find out if my number is in the first column, if it found it, return the value for the second column

For a sample my number is 66 it must return 594

Posted: **Sat May 28, 2022 6:59 pm**

Code: Select all | Expand

function ArrLookUp( aArray, nSeek )

   local nAt
   
   if ( nAt := AScan( aArray, { |a| a[ 1 ] == nSeek } ) ) > 0
      return aArray[ nAt, 2 ]
   endif
   
return nil

Posted: **Sat May 28, 2022 7:30 pm**

thanks

FiveTech Software tech support forums

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